2013 ppt batfink projectile review

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Page 1: 2013 ppt batfink projectile review
Page 2: 2013 ppt batfink projectile review
Page 3: 2013 ppt batfink projectile review

Know Definitio

ns of Key

Terms & Symbols

Page 4: 2013 ppt batfink projectile review

Focus during the entire Power Point activity. Solidify your studying skills during this class period.

Perform your work in your science journal so you have created a study guide for the test.

Call me over if you are having difficulty getting started.

If your answer is confirmed as correct, become a student/teacher and help someone in class who does not understand the method used to solve the problem.

Page 5: 2013 ppt batfink projectile review

Hugo Ago-go pushes the barrel with Batfink in it towards the end of the cliff with a 85 N force over a distance of 12 m before the barrel leaves the cliff. The force of friction is 7 N. Draw a force diagram of the situation.

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y

Fs 735 N

Ff 2.25 N Fa 85 N x

Fg 735 N

Page 7: 2013 ppt batfink projectile review

Calculate the acceleration

of the barrel in the xaxis.

Page 8: 2013 ppt batfink projectile review

SOLUTION:Acceleration of Batfink and the barrel.

mbf = 50 kg amb = 25 kgg = -9.8 m/s2

Fa = 85 NFf = 7 NXi = 0 mXf = 12 m a = 1.04 m/s2

Page 9: 2013 ppt batfink projectile review

What is the Vf of the

barrel just before it falls

off the cliff?

Page 10: 2013 ppt batfink projectile review

SOLUTION:Final velocity of Batfink and the barrel while still on the cliff.

mbf = 50 kg amb = 25 kga = 1.04 m/s2

g = -9.8 m/s2

Fa = 85 NFf = 7 NXi = 0 mXf = 12 m Vx = 5 m/s

Page 11: 2013 ppt batfink projectile review

Batfink is pushed off of the 52 meter

high Canadian Horseshoe Fallstowards the dried up Maid of theMist pool. How much time willBatfink have to escape from thebarrel once it leaves the cliff?

Page 12: 2013 ppt batfink projectile review

SOLUTION:Maximum time for escape.

Vi = 0 m/s tf

g = -9.8 m/s2 Vf

Yf = 0 mYi = 52 mti = 0 s t = 3.26 s

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SOLUTION:Final velocity of Batfink and the barrel.

Vi = 0 m/s Vf

g = -9.8 m/s2

Yi = 52 mYf = 0 mti = 0 s tf = 3.19 s Vf = -31.95 m/s

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SOLUTION:Final velocity of Batfink and the barrel.

Vyi = 0 m/s Xf

g = -9.8 m/s2

Yi = 52 mYf = 0 mti = 0 s tf = 3.19 s Xf = 16.3 mVyf = -31.3 m/s

Page 17: 2013 ppt batfink projectile review