12 x1 t07 02 simple harmonic motion
TRANSCRIPT
Simple Harmonic Motion
Simple Harmonic MotionA particle that moves back and forward in such a way that its acceleration at any instant is directly proportional to its distance from a fixed point, is said to undergo Simple Harmonic Motion (SHM)
Simple Harmonic MotionA particle that moves back and forward in such a way that its acceleration at any instant is directly proportional to its distance from a fixed point, is said to undergo Simple Harmonic Motion (SHM)
xx
Simple Harmonic MotionA particle that moves back and forward in such a way that its acceleration at any instant is directly proportional to its distance from a fixed point, is said to undergo Simple Harmonic Motion (SHM)
xx kxx
Simple Harmonic MotionA particle that moves back and forward in such a way that its acceleration at any instant is directly proportional to its distance from a fixed point, is said to undergo Simple Harmonic Motion (SHM)
xx kxx
xnx 2
Simple Harmonic MotionA particle that moves back and forward in such a way that its acceleration at any instant is directly proportional to its distance from a fixed point, is said to undergo Simple Harmonic Motion (SHM)
xx kxx
xnx 2 (constant needs to be negative)
Simple Harmonic MotionA particle that moves back and forward in such a way that its acceleration at any instant is directly proportional to its distance from a fixed point, is said to undergo Simple Harmonic Motion (SHM)
xx
xnx 2
obeys;it then SHM, undergoes particle a If
kxx xnx 2 (constant needs to be negative)
Simple Harmonic MotionA particle that moves back and forward in such a way that its acceleration at any instant is directly proportional to its distance from a fixed point, is said to undergo Simple Harmonic Motion (SHM)
xx
xnx 2
obeys;it then SHM, undergoes particle a If
xnvdxd 22
21
kxx xnx 2 (constant needs to be negative)
Simple Harmonic MotionA particle that moves back and forward in such a way that its acceleration at any instant is directly proportional to its distance from a fixed point, is said to undergo Simple Harmonic Motion (SHM)
xx
xnx 2
obeys;it then SHM, undergoes particle a If
xnvdxd 22
21
cxnv
cxnv
222
222
21
21
kxx xnx 2 (constant needs to be negative)
when x = a , v = 0 (a = amplitude)
22
2220 i.e.
anc
can
when x = a , v = 0 (a = amplitude)
22
2220 i.e.
anc
can
22
2222
22222
xanv
xanv
anxnv
when x = a , v = 0 (a = amplitude)
22
2220 i.e.
anc
can
22
2222
22222
xanv
xanv
anxnv
NOTE: 02 v
when x = a , v = 0 (a = amplitude)
22
2220 i.e.
anc
can
22
2222
22222
xanv
xanv
anxnv
NOTE: 02 v
022 xa
when x = a , v = 0 (a = amplitude)
22
2220 i.e.
anc
can
22
2222
22222
xanv
xanv
anxnv
NOTE: 02 v
022 xa
axa
when x = a , v = 0 (a = amplitude)
22
2220 i.e.
anc
can
22
2222
22222
xanv
xanv
anxnv
NOTE: 02 v
022 xa
axa
Particle travels back and forward between x = -a and x = a
when x = a , v = 0 (a = amplitude)
22 xandtdx
22 xandtdx
1-
1-
sin and ve choose ,0
cos and ve- choose ,
;0 when If
x
ax
t
22 xandtdx
1-
1-
sin and ve choose ,0
cos and ve- choose ,
;0 when If
x
ax
t
22
1
xandxdt
22 xandtdx
1-
1-
sin and ve choose ,0
cos and ve- choose ,
;0 when If
x
ax
t
22
1
xandxdt
dxxan
tx
a
22
11
22 xandtdx
1-
1-
sin and ve choose ,0
cos and ve- choose ,
;0 when If
x
ax
t
22
1
xandxdt
dxxan
tx
a
22
11
x
aax
n
1cos
1
22 xandtdx
1-
1-
sin and ve choose ,0
cos and ve- choose ,
;0 when If
x
ax
t
22
1
xandxdt
dxxan
tx
a
22
11
x
aax
n
1cos
1
ax
n
ax
n
1
11
cos1
1coscos1
22 xandtdx
1-
1-
sin and ve choose ,0
cos and ve- choose ,
;0 when If
x
ax
t
22
1
xandxdt
dxxan
tx
a
22
11
x
aax
n
1cos
1
ax
n
ax
n
1
11
cos1
1coscos1
ntax
ntax
ax
nt
cos
cos
cos 1
In general;
In general;
xnx 2
obeys SHM undergoing particleA
In general;
xnx 2
obeys SHM undergoing particleA
2222 xanv
In general;
xnx 2
obeys SHM undergoing particleA
2222 xanv particle theofpath find tous allows
In general;
xnx 2
obeys SHM undergoing particleA
2222 xanv particle theofpath find tous allows
ntax cos
In general;
xnx 2
obeys SHM undergoing particleA
2222 xanv particle theofpath find tous allows
ntax cosamplitude where
sin OR
a
ntax
In general;
xnx 2
obeys SHM undergoing particleA
2222 xanv particle theofpath find tous allows
ntax cosamplitude where
sin OR
a
ntax
the particle has;
In general;
xnx 2
obeys SHM undergoing particleA
2222 xanv particle theofpath find tous allows
ntax cosamplitude where
sin OR
a
ntax
the particle has;
Tf
nT
1 :frequency
2 :period
In general;
xnx 2
obeys SHM undergoing particleA
2222 xanv particle theofpath find tous allows
ntax cosamplitude where
sin OR
a
ntax
the particle has;
Tf
nT
1 :frequency
2 :period
(time for one oscillation)
In general;
xnx 2
obeys SHM undergoing particleA
2222 xanv particle theofpath find tous allows
ntax cosamplitude where
sin OR
a
ntax
the particle has;
Tf
nT
1 :frequency
2 :period
(time for one oscillation)
(number of oscillations per time period)
e.g. (i) A particle, P, moves on the x axis according to the law x = 4sin3t.
e.g. (i) A particle, P, moves on the x axis according to the law x = 4sin3t.
a) Show that P is moving in SHM and state the period of motion.
e.g. (i) A particle, P, moves on the x axis according to the law x = 4sin3t.
a) Show that P is moving in SHM and state the period of motion.
tx
tx
tx
3sin36
3cos12
3sin4
e.g. (i) A particle, P, moves on the x axis according to the law x = 4sin3t.
a) Show that P is moving in SHM and state the period of motion.
tx
tx
tx
3sin36
3cos12
3sin4
x9
e.g. (i) A particle, P, moves on the x axis according to the law x = 4sin3t.
a) Show that P is moving in SHM and state the period of motion.
tx
tx
tx
3sin36
3cos12
3sin4
x9SHMin moves particle
e.g. (i) A particle, P, moves on the x axis according to the law x = 4sin3t.
a) Show that P is moving in SHM and state the period of motion.
tx
tx
tx
3sin36
3cos12
3sin4
x9SHMin moves particle
32T
e.g. (i) A particle, P, moves on the x axis according to the law x = 4sin3t.
a) Show that P is moving in SHM and state the period of motion.
tx
tx
tx
3sin36
3cos12
3sin4
x9SHMin moves particle
32T
seconds 3
2 ismotion of period
e.g. (i) A particle, P, moves on the x axis according to the law x = 4sin3t.
a) Show that P is moving in SHM and state the period of motion.
tx
tx
tx
3sin36
3cos12
3sin4
x9SHMin moves particle
32T
seconds 3
2 ismotion of period
b) Find the interval in which the particle moves and determine the greatest speed.
e.g. (i) A particle, P, moves on the x axis according to the law x = 4sin3t.
a) Show that P is moving in SHM and state the period of motion.
tx
tx
tx
3sin36
3cos12
3sin4
x9SHMin moves particle
32T
seconds 3
2 ismotion of period
b) Find the interval in which the particle moves and determine the greatest speed.
units/s 12 is speedgreatest theand
44 interval thealong moves particle x
(ii) A particle moves so that its acceleration is given byInitially the particle is 3cm to the right of O and traveling with a velocity of 6cm/s.Find the interval in which the particle moves and determine the greatest acceleration.
xx 4
(ii) A particle moves so that its acceleration is given byInitially the particle is 3cm to the right of O and traveling with a velocity of 6cm/s.Find the interval in which the particle moves and determine the greatest acceleration.
xx 4
xvdxd
421 2
(ii) A particle moves so that its acceleration is given byInitially the particle is 3cm to the right of O and traveling with a velocity of 6cm/s.Find the interval in which the particle moves and determine the greatest acceleration.
xx 4
xvdxd
421 2
cxv
cxv
22
22
4
221
(ii) A particle moves so that its acceleration is given byInitially the particle is 3cm to the right of O and traveling with a velocity of 6cm/s.Find the interval in which the particle moves and determine the greatest acceleration.
xx 4
xvdxd
421 2
cxv
cxv
22
22
4
221
72
346 i.e.
6,3when 22
c
c
vx
(ii) A particle moves so that its acceleration is given byInitially the particle is 3cm to the right of O and traveling with a velocity of 6cm/s.Find the interval in which the particle moves and determine the greatest acceleration.
xx 4
xvdxd
421 2
cxv
cxv
22
22
4
221
72
346 i.e.
6,3when 22
c
c
vx
724 22 xv
(ii) A particle moves so that its acceleration is given byInitially the particle is 3cm to the right of O and traveling with a velocity of 6cm/s.Find the interval in which the particle moves and determine the greatest acceleration.
xx 4
xvdxd
421 2
cxv
cxv
22
22
4
221
72
346 i.e.
6,3when 22
c
c
vx
2323
18
0724
0But
2
2
2
x
x
x
v
724 22 xv
(ii) A particle moves so that its acceleration is given byInitially the particle is 3cm to the right of O and traveling with a velocity of 6cm/s.Find the interval in which the particle moves and determine the greatest acceleration.
xx 4
xvdxd
421 2
cxv
cxv
22
22
4
221
72
346 i.e.
6,3when 22
c
c
vx
2323
18
0724
0But
2
2
2
x
x
x
v
724 22 xv
212
234,23when
xx
(ii) A particle moves so that its acceleration is given byInitially the particle is 3cm to the right of O and traveling with a velocity of 6cm/s.Find the interval in which the particle moves and determine the greatest acceleration.
xx 4
xvdxd
421 2
cxv
cxv
22
22
4
221
72
346 i.e.
6,3when 22
c
c
vx
2323
18
0724
0But
2
2
2
x
x
x
v
724 22 xv
212
234,23when
xx
2cm/s 212 ison acceleratigreatest
NOTE:
NOTE: At amplitude;v = 0
a is maximum
NOTE: At amplitude;v = 0
a is maximum
At centre;v is maximum
a = 0
Exercise 3D; 1, 6, 7, 10, 12, 14ab, 15ab, 18, 19, 22, 24, 25(start with trig, prove SHM or are told)
Exercise 3F; 1, 4, 5b, 6b, 8, 9a, 10a, 13, 14 a, b(ii,iv), 16, 18, 19(start with )
NOTE: At amplitude;v = 0
a is maximum
At centre;v is maximum
a = 0
xnx 2