11 x1 t08 07 asinx + bcosx = c (2012)

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Equations of the form asinx + bcosx = c Method 1: Using the t results

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Page 1: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

Page 2: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2

Page 3: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2

let tan2

t

Page 4: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

Page 5: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t

Page 6: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t 25 8 1 0t t

Page 7: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t 25 8 1 0t t

8 8410

t

Page 8: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t 25 8 1 0t t

8 8410

t

4 21 4 21tan or tan2 5 2 5

Page 9: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t 25 8 1 0t t

8 8410

t

4 21 4 21tan or tan2 5 2 5

Q2

Page 10: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t 25 8 1 0t t

8 8410

t

4 21 4 21tan or tan2 5 2 5

Q2 21 4tan5

6 39

Page 11: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t 25 8 1 0t t

8 8410

t

4 21 4 21tan or tan2 5 2 5

Q2 21 4tan5

6 39

173 212

346 42

Page 12: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t 25 8 1 0t t

8 8410

t

4 21 4 21tan or tan2 5 2 5

Q2 21 4tan5

6 39

173 212

346 42

Q1

Page 13: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t 25 8 1 0t t

8 8410

t

4 21 4 21tan or tan2 5 2 5

Q2 21 4tan5

6 39

173 212

346 42

Q1 4 21tan5

59 47

Page 14: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t 25 8 1 0t t

8 8410

t

4 21 4 21tan or tan2 5 2 5

Q2 21 4tan5

6 39

173 212

346 42

Q1 4 21tan5

59 47

59 472

119 33

Page 15: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t 25 8 1 0t t

8 8410

t

4 21 4 21tan or tan2 5 2 5

Q2 21 4tan5

6 39

173 212

346 42

Q1 4 21tan5

59 47

59 472

119 33

180: Test

Page 16: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t 25 8 1 0t t

8 8410

t

4 21 4 21tan or tan2 5 2 5

Q2 21 4tan5

6 39

173 212

346 42

Q1 4 21tan5

59 47

59 472

119 33

180: Test

3cos180 4sin1804 2

Page 17: 11 x1 t08 07 asinx + bcosx = c (2012)

Equations of the form asinx + bcosx = cMethod 1: Using the t results

3600 eg (i) 3cos 4sin 2 2

2 21 23 4 2 0 1801 1 2

t tt t

let tan

2t

2 23 3 8 2 2t t t 25 8 1 0t t

8 8410

t

4 21 4 21tan or tan2 5 2 5

Q2 21 4tan5

6 39

173 212

346 42

Q1 4 21tan5

59 47

59 472

119 33

180: Test

3cos180 4sin1804 2

119 33 ,346 42

Page 18: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

Page 19: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

Page 20: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

sincoscossin

Page 21: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

sincoscossin

Page 22: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

sincoscossin

sin corresponds to 3, so 3 goes on the opposite

side

3

Page 23: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

sincoscossin

3

Page 24: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

sincoscossin

3

cos corresponds to 4, so 4 goes on the adjacent

side

4

Page 25: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

sincoscossin

3

4

by Pythagoras the hypotenuse is 5

5

Page 26: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

sincoscossin

3

4

by Pythagoras the hypotenuse is 5

5

3 45 cos sin 25 5

Page 27: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

sincoscossin

3

4

by Pythagoras the hypotenuse is 5

5

5sin 2

3 45 cos sin 25 5

Page 28: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

sincoscossin

3

4

by Pythagoras the hypotenuse is 5

5

5sin 2

The hypotenuse becomes the coefficient of the trig function

3 45 cos sin 25 5

Page 29: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

3

4

5

5sin 2

3 45 cos sin 25 5

3tan

4

2sin5

Page 30: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

3

4

5

5sin 2

3 45 cos sin 25 5

3tan

4

36 52 2sin5

Page 31: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

3

4

5

5sin 2

3 45 cos sin 25 5

3tan

4

36 52 2sin5

Q1, Q2

Page 32: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

3

4

5

5sin 2

3 45 cos sin 25 5

3tan

4

36 52 2sin5

Q1, Q2

2sin5

Page 33: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

3

4

5

5sin 2

3 45 cos sin 25 5

3tan

4

36 52 2sin5

Q1, Q2

2sin5

23 35

Page 34: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

3

4

5

5sin 2

3 45 cos sin 25 5

3tan

4

36 52 2sin5

Q1, Q2

2sin5

23 35

36 52 23 35 ,156 25

Page 35: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

3

4

5

5sin 2

3 45 cos sin 25 5

3tan

4

36 52 2sin5

Q1, Q2

2sin5

23 35

36 52 23 35 ,156 25

13 17 ,119 33

Page 36: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(i) Change into a sine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

3

4

5

5sin 2

3 45 cos sin 25 5

3tan

4

36 52 2sin5

Q1, Q2

2sin5

23 35

36 52 23 35 ,156 25 119 33 ,346 43

13 17 ,119 33

Page 37: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

Page 38: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

Page 39: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

Page 40: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

Page 41: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

cos corresponds to 3, so 3 goes on the adjacent

side

3

Page 42: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

Page 43: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

cos corresponds to 4, so 4 goes on the adjacent

side

4

Page 44: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

4

by Pythagoras the hypotenuse is 5

5

Page 45: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

4

by Pythagoras the hypotenuse is 5

5

3 45 cos sin 25 5

Page 46: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

4

by Pythagoras the hypotenuse is 5

5

5cos 2

3 45 cos sin 25 5

Page 47: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

4

by Pythagoras the hypotenuse is 5

5

5cos 2

The hypotenuse becomes the coefficient of the trig function

3 45 cos sin 25 5

Page 48: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

45

5cos 2

3 45 cos sin 25 5

4tan

3

2cos5

Page 49: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

45

5cos 2

3 45 cos sin 25 5

4tan

3

53 8 2cos5

Page 50: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

45

5cos 2

3 45 cos sin 25 5

4tan

3

53 8 2cos5

Q1, Q4

Page 51: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

45

5cos 2

3 45 cos sin 25 5

4tan

3

53 8 2cos5

Q1, Q4

2cos5

Page 52: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

45

5cos 2

3 45 cos sin 25 5

4tan

3

53 8 2cos5

Q1, Q4

2cos5

66 25

Page 53: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

45

5cos 2

3 45 cos sin 25 5

4tan

3

53 8 2cos5

Q1, Q4

2cos5

66 25

53 8 66 25 ,293 35

Page 54: 11 x1 t08 07 asinx + bcosx = c (2012)

Method 2: Auxiliary Angle Method(ii) Change into a cosine functioneg (i) 3cos 4sin 2 3600

3cos 4sin 2

cos cos sin sin

3

45

5cos 2

3 45 cos sin 25 5

4tan

3

53 8 2cos5

Q1, Q4

2cos5

66 25

53 8 66 25 ,293 35

119 33 ,346 43

Page 55: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

Page 56: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t

Page 57: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

Page 58: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12

Page 59: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12 2sin 3t

Page 60: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12 2sin 3t

1tan3

30

Page 61: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12 2sin 3t

1tan3

30

2sin 3 30t

Page 62: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12 2sin 3t

1tan3

30

2sin 3 30t

(iii) Express sin cos in the form cosx x R x 2003 Extension 1 HSC Q2e) (i)

Page 63: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12 2sin 3t

1tan3

30

2sin 3 30t

(iii) Express sin cos in the form cosx x R x 2003 Extension 1 HSC Q2e) (i)

sin cosx x

Page 64: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12 2sin 3t

1tan3

30

2sin 3 30t

(iii) Express sin cos in the form cosx x R x 2003 Extension 1 HSC Q2e) (i)

sin cosx x cos cos sin sinx x

Page 65: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12 2sin 3t

1tan3

30

2sin 3 30t

(iii) Express sin cos in the form cosx x R x 2003 Extension 1 HSC Q2e) (i)

sin cosx x cos cos sin sinx x

cos sinx x

Page 66: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12 2sin 3t

1tan3

30

2sin 3 30t

(iii) Express sin cos in the form cosx x R x 2003 Extension 1 HSC Q2e) (i)

sin cosx x cos cos sin sinx x

1

12 cos sinx x

Page 67: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12 2sin 3t

1tan3

30

2sin 3 30t

(iii) Express sin cos in the form cosx x R x 2003 Extension 1 HSC Q2e) (i)

sin cosx x cos cos sin sinx x

1

12

2 cos x cos sinx x

Page 68: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12 2sin 3t

1tan3

30

2sin 3 30t

(iii) Express sin cos in the form cosx x R x 2003 Extension 1 HSC Q2e) (i)

sin cosx x cos cos sin sinx x

1

12

2 cos x

tan 145

cos sinx x

Page 69: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12 2sin 3t

1tan3

30

2sin 3 30t

(iii) Express sin cos in the form cosx x R x 2003 Extension 1 HSC Q2e) (i)

sin cosx x cos cos sin sinx x

1

12

2 cos x

tan 145

2 cos 45x

cos sinx x

Page 70: 11 x1 t08 07 asinx + bcosx = c (2012)

(ii) Express 3sin 3 cos3 in the form sin 3t t R t 2005 Extension 1 HSC Q5c) (i)

3sin3 cos3t t sin 3 cos cos3 sint t

3

12 2sin 3t

1tan3

30

2sin 3 30t

(iii) Express sin cos in the form cosx x R x 2003 Extension 1 HSC Q2e) (i)

sin cosx x cos cos sin sinx x

1

12

2 cos x

tan 145

2 cos 45x

cos sinx x

Exercise 2E;6, 7, 10bd, 11, 13, 14, 16ac, 20a, 23