11 x1 t02 02 rational & irrational (2013)

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Rational Numbers

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Page 1: 11 x1 t02 02 rational & irrational (2013)

Rational Numbers

Page 2: 11 x1 t02 02 rational & irrational (2013)

Rational NumbersRational numbers can be expressed in the form where a and b are integers. b

a

Page 3: 11 x1 t02 02 rational & irrational (2013)

Rational NumbersRational numbers can be expressed in the form where a and b are integers. b

a

Irrational Numbers

Page 4: 11 x1 t02 02 rational & irrational (2013)

Rational NumbersRational numbers can be expressed in the form where a and b are integers. b

a

Irrational NumbersIrrational numbers are numbers which are not rational.

All irrational numbers can be expressed as a unique infinite decimal.

Page 5: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge

Page 6: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

Page 7: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

Page 8: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

Page 9: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

ab 2

Page 10: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

ab 2222 ab

Page 11: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

ab 2222 ab

2by divisible bemust Thus 2a

Page 12: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

ab 2222 ab

2by divisible bemust Thus 2a4by divisible is2by divisibleisthat squareAny

Page 13: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

ab 2222 ab

2by divisible bemust Thus 2a4by divisible is2by divisibleisthat squareAny

4by divisible bemust Thus 2a

Page 14: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

ab 2222 ab

2by divisible bemust Thus 2a4by divisible is2by divisibleisthat squareAny

4by divisible bemust Thus 2a2 2 4b k where k is an integer

Page 15: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

ab 2222 ab

2by divisible bemust Thus 2a4by divisible is2by divisibleisthat squareAny

4by divisible bemust Thus 2a2 2 4b k where k is an integer2 2b k

Page 16: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

ab 2222 ab

2by divisible bemust Thus 2a4by divisible is2by divisibleisthat squareAny

4by divisible bemust Thus 2a2 2 4b k

factorcommon a havemust and 2by divisibleboth are and So 22 ba

where k is an integer2 2b k

Page 17: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

ab 2222 ab

2by divisible bemust Thus 2a4by divisible is2by divisibleisthat squareAny

4by divisible bemust Thus 2a2 2 4b k

factorcommon a havemust and 2by divisibleboth are and So 22 baHowever, a and b have no common factors

where k is an integer2 2b k

Page 18: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

ab 2222 ab

2by divisible bemust Thus 2a4by divisible is2by divisibleisthat squareAny

4by divisible bemust Thus 2a2 2 4b k

factorcommon a havemust and 2by divisibleboth are and So 22 baHowever, a and b have no common factors

rationalnot is 2so

where k is an integer2 2b k

Page 19: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

ab 2222 ab

2by divisible bemust Thus 2a4by divisible is2by divisibleisthat squareAny

4by divisible bemust Thus 2a2 2 4b k

factorcommon a havemust and 2by divisibleboth are and So 22 baHowever, a and b have no common factors

rationalnot is 2soirrational is2

where k is an integer2 2b k

Page 20: 11 x1 t02 02 rational & irrational (2013)

irrational is 2 Prove ..ge“Proof by contradiction”

rationalis 2 Assume

ba

2 where a and b are integers with no common factors

ab 2222 ab

2by divisible bemust Thus 2a4by divisible is2by divisibleisthat squareAny

4by divisible bemust Thus 2a2 2 4b k

factorcommon a havemust and 2by divisibleboth are and So 22 baHowever, a and b have no common factors

rationalnot is 2soirrational is2 Exercise 2B; 2a, 3, 4 (root 3), 8, 14*

where k is an integer2 2b k