T

s N

θ

M

Q LINE SQ AND PLANE SMTN

ORTHOGONAL PROJECTION

OF LINE SQ ON PLANE SMTN

= LINE ST

SO ANGLE QST

Example:

T

s N

θ

M

Q

Garis SQ dgn satah SMTN

KAEDAH POTONG

Example:

S Q

S M T N

Q_ S__T_

1. POTONG YG SAMA DAN LETAK DI TENGAH2. YG TINGGAL DIDEPAN

3.DARI Q KE TAK POTONGCARI YG PALING DEKAT. - QT

P

S

T

U

R

Q

V5 CM

12 cm

Diagram shows a right prism. The base PQRS is a horizontal rectangle. Right angled triangle QRU is uniform cross-section of the prism. V is the mid-point of PS.

Identify and calculate the angle between the line UV and the plane RSTU. Spm 2007

0 ''

8tan

13

= 31 36

θ =16

cm

13

V

S U

8

θ

U V

RSTU V U S

AM SUDUT MAE

A

E M

θ

4

15

ADEF

θ

A

G

F

E

D

CB

H

I

STEPS : 1. POTONG YG SAMA

2. YG TINGGAL E, F - DIDEPAN

3. E KE YG POTONG - C @ D

EFCD ABCD

E D A F C B

4. E KE YG TAK POTONG - A @ B

θ

N

E

D N

5

6.5 cm

θ

AEC

ABCD

E DEPAN

5tan

6.5 = 37.57

θ =

EA = EC

∠ E N D

SPM 2009

(a)Nama the angle between the plane BCJ and the base ABCD

(b)Calculate the angle between the plane BCJ and the base ABCD.

D

1. :

2.

BCJ

SPM 2009

4

ABCD

∠ J B A

SLN SRMN

L N M

∠LNM tan ∠LNM = or equivalent 36.87o or 36o 52’

(i) Marked Angle between BCHG and ABCD(ii) Calculate the angle

20' 51or 34.51

4

5ABG Tan

oo=

=∠

=

=∠10

6 DCETan (b)

ECD / DCE (a)

Kesilapan Pelajar:

(a) Tidak menanda sudut / menyatakan sudut

(b) Tidak semestinya menggunakan Tan.

(c) Pengiraan sisi yang salah (d) Membulatkan Jawapan.

spm2011