1 kyung hee university chapter 6 multiplexing. 2 kyung hee university 6 장 다중화 (multiplexing)...
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Chapter 6Chapter 6 Multiplexing Multiplexing
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6 6 장 다중화장 다중화 (Multiplexing)(Multiplexing)
Dividing a link into channels
• Word link refers to the physical path• Channel refers to the portion of a link that carries a transmission between a given pair of lines.
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다중화다중화 (Multiplexing)(Multiplexing)
다중화 (Multiplexing)
is the set of techniques that allows the simultaneous transmission of multiple signals across a single data link.
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6.1 FDM6.1 FDM
다중화기 (Multiplexer)
transmission streams combine into a single stream(many to one)
역다중화기 (Demultiplexer)
stream separates into its component transmission(one to many) and directs them to their intended receiving devices
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8.2 8.2 Many to One/One to ManyMany to One/One to Many
Categories of Multiplexing
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FDMFDM
FDM(Frequency-Division Multiplexing)
is an analog technique that can be applied when the bandwidth of a link is greater than the combined bandwidths of the signals to be transmitted
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FDM (cont’d)FDM (cont’d)
FDM process
each telephone generates a signal of a similar frequency range
these signals are modulated onto different carrier frequencies(f1, f2, f3)
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FDM (cont’d)FDM (cont’d)
FDM multiplexing process, time-domain
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FDM(cont’d)FDM(cont’d)
FDM multiplexing process, frequency-domain
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FDM(cont’d)FDM(cont’d)
Demultiplexing
separates the individual signals from their carries and passes them to the waiting receivers.
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FDM(cont’d)FDM(cont’d)
FDM demultiplexing process, time-domain
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FDM(cont’d)FDM(cont’d)
FDM demultiplexing, frequency-domain
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Example 1Example 1
Example 1Example 1
Assume that a voice channel occupies a bandwidth of 4 KHz. We need to combine three voice channels into a link with a bandwidth of 12 KHz, from 20 to 32 KHz. Show the configuration using the frequency domain without the use of guard bands.
SolutionSolution
Shift (modulate) each of the three voice channels to a different bandwidth, as shown in Figure 6.6.
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Example 1 (cont’d)Example 1 (cont’d)
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Example 2Example 2
Example 2Example 2
Five channels, each with a 100-KHz bandwidth, are to be multiplexed together. What is the minimum bandwidth of the link if there is a need for a guard band of 10 KHz between the channels to prevent interference?
SolutionSolution
For five channels, we need at least four guard bands. This means that the required bandwidth is at least 5 x 100 + 4 x 10 = 540 KHz, as shown in Figure 6.7.
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Example 2 (cont’d)Example 2 (cont’d)
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Example 3Example 3
Example 3Example 3
Four data channels (digital), each transmitting at 1 Mbps, use a satellite channel of 1 MHz. Design an appropriate configuration using FDM
SolutionSolution
The satellite channel is analog. We divide it into four channels, each channel having a 250-KHz bandwidth. Each digital channel of 1 Mbps is modulated such that each 4 bits are modulated to 1 Hz. One solution is 16-QAM modulation. Figure 6.8 shows one possible configuration.
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Example 3 (cont’d)Example 3 (cont’d)
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FDM(cont’d)FDM(cont’d)
Example : Cable Television
coaxial cable has a bandwidth of approximately 500Mhz
individual television channel require about 6Mhz of bandwidth for transmission
can carry 83 channels theoretically
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Analog HierarchyAnalog Hierarchy
To maximize the efficiency of their infrastructure, telephone companies have traditionally multiplexed signals from lower bandwidth lines onto higher bandwidth lines.
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Applications of FDMApplications of FDM
Example 4Example 4The Advanced Mobile Phone System (AMPS) uses two bands. The first band, 824 to 849 MHz, is used for sending; and 869 to 894 MHz is used for receiving. Each user has a bandwidth of 30 KHz in each direction. The 3-KHz voice is modulated using FM, creating 30 KHz of modulated signal. How many people can use their cellular phones simultaneously?
SolutionSolution
Each band is 25 MHz. If we divide 25 MHz into 30 KHz, we get 833.33. In reality, the band is divided into 832 channels.
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6.2 Wave Division Multiplexing (WDM)6.2 Wave Division Multiplexing (WDM)
WDM is conceptually same as FDM
except that the multiplexing and demultiplexing involve light signals transmitted through fiber-optic channels
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WDM (cont’d)WDM (cont’d)
WDM is an analog multiplexing technique to
combine optical signals.
Very narrow bands of light from different sources are combined to make a wider band of light
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WDM (cont’d)WDM (cont’d)
Combining and splitting of light sources are easily
handled by a prism
Prism bends a beam of light based on the angle of incidence and the frequency.
One application is the SONET.
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6.3 TDM6.3 TDM
TDM(Time-Division Multiplexing)
is a digital process that can be applied when the data rate capacity of the transmission medium is greater than the data rate required by the sending and receiving device
TDM is a digital multiplexing technique to combine data.
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TDM(cont’d)TDM(cont’d)
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TDM (cont’d)TDM (cont’d)
In a TDM, the data rate of the link is n times faster, and the unit duration is n times shorter.In a TDM, the data rate of the link is n times faster, and the unit duration is n times shorter.
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TDM (cont’d)TDM (cont’d)
Example 5Example 5Four 1-Kbps connections are multiplexed together. A unit is 1 bit. Find (1) the duration of 1 bit before multiplexing, (2) the transmission rate of the link, (3) the duration of a time slot, and (4) the duration of a frame?
SolutionSolution
We can answer the questions as follows:
1. The duration of 1 bit is 1/1 Kbps, or 0.001 s (1 ms).2. The rate of the link is 4 Kbps.3. The duration of each time slot 1/4 ms or 250 s. 4. The duration of a frame 1 ms.
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TDM(cont’d)TDM(cont’d)
TDM can be implemented in two ways
Synchronous TDM
Asynchronous TDM
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TDM(cont’d)TDM(cont’d)
Synchronous TDM
the multiplexer allocates exactly the same time slot to each device at all times, whether or not a device has anything to transmit.
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TDM(cont’d)TDM(cont’d)
Frame
Time slots are grouped into frames
A frame consists of one complete cycle of time slots, including one or more slots dedicated to each sending device, plus framing bits.
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TDM(cont’d)TDM(cont’d)
Synchronous TDM
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TDM(cont’d)TDM(cont’d)Interleaving
synchronous TDM can be compared to a very fast rotating switch
switch moves from device to device at a constant rate and in a fixed order
6 empty slots out of 24 are being wasted
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TDM(cont’d)TDM(cont’d)
Demultiplexer decomposes each frame by discarding th
e framing bits and extracting each character in turn
Synchronous TDM, demultiplexing process
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TDM(cont’d)TDM(cont’d)
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TDM(cont’d)TDM(cont’d)
Example 6Example 6Four channels are multiplexed using TDM. If each channel sends 100 bytes/s and we multiplex 1 byte per channel, show the frame traveling on the link, the size of the frame, the duration of a frame, the frame rate, and the bit rate for the link.
SolutionSolution
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TDM(cont’d)TDM(cont’d)
Example 7Example 7
A multiplexer combines four 100-Kbps channels using a time slot of 2 bits. Show the output with four arbitrary inputs. What is the frame rate? What is the frame duration? What is the bit rate? What is the bit duration?
SolutionSolution
Figure 6.16 shows the output for four arbitrary inputs.
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TDM(cont’d)TDM(cont’d)
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TDM(cont’d)TDM(cont’d)
Framing bits
~ allows the demultiplexer to synchronize with the incoming stream so that it can separate the time slots accurately
(ex: 01010101 ….)
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TDM(cont’d)TDM(cont’d)
Synchronous TDM Example4 characters + 1 framing bit
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TDM(cont’d)TDM(cont’d)
Asynchronous TDM : statistical time-division multiplexing
Synchronous or Asynchronous : Not flexible or Flexible
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TDM(cont’d)TDM(cont’d)
Examples of asynchronous TDM frames
a. Case 1: Only three lines sending data
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TDM(cont’d)TDM(cont’d)
b. Case 2: Only four lines sending data
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TDM(cont’d)TDM(cont’d)
c. Case 3: All five lines sending data
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Multiplexing application(cont’d)Multiplexing application(cont’d)
Analog Hierarchy
To maximize the efficiency of their infrastructure, telephone companies have traditionally multiplexed signals from lower bandwidth lines onto higher bandwidth lines.
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Multiplexing application(cont’d)Multiplexing application(cont’d)
Digital Services
advantage
- less sensitive than analog service to noise
- lower cost
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Multiplexing application(cont’d)Multiplexing application(cont’d)
DS(Digital Signal) Service
~ is a hierarchy of digital signal
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Multiplexing application(cont’d)Multiplexing application(cont’d)
DS Service
DS-0 : single digital channel of 64Kbps
DS-1 : 1,544Mbps, 24 개의 64Kbps + 8Kbps 의 overhead
DS-2 : 6,312Mbps, 96 개의 64Kbps+168Kbps 의 overhead
DS-3 : 44,376Mbps, 672 개의 64Kbps+1.368Mbps 의
overhead
DS-4 : 274,176Mbps,4032 개의 64Kbps+16.128Mbps 의
overhead
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Multiplexing application(cont’d)Multiplexing application(cont’d)
T Lines
Service Line Rate(Mbps) Voice Channels
DS-1
DS-2
DS-3
DS-4
T-1
T-2
T-3
T-4
1,544
6,312
44,736
274,176
24
96
672
4032
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5050
Kyung Hee University
T Lines for Analog Transmission
T-1 line for multiplexing telephone lines
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5151
Kyung Hee University
T-1 FrameT-1 Frame
193 = 24 x 8 + 1(1 bit for synchronization)
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5252
Kyung Hee University
E LinesE Lines
E line rates
E LineRate
(Mbps)
Voice
Channels
E-1E-1 2.0482.048 3030
E-2E-2 8.4488.448 120120
E-3E-3 34.36834.368 480480
E-4E-4 139.264139.264 19201920
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5353
Kyung Hee University
TDM(cont’d)TDM(cont’d)
Inverse Multiplexing
takes the data stream from one high-speed line and breaks it into portion that can be sent across several lower speed lines simultaneously, with no loss in the collective data rate
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5454
Kyung Hee University
TDM(cont’d)TDM(cont’d)
Multiplexing and inverse multiplexing
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5555
Kyung Hee University
TDM(cont’d)TDM(cont’d)
Why do we need inverse multiplexing ?
wants to send data, voice, and video each of which requires a different data rate.
[example]
voice - 64 Kbps link
data - 128 Kbps link
video - 1,544 Mbps link