1 electrical technology eet 103/4 explain and analyze series and parallel circuits explain, derive...
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ELECTRICAL TECHNOLOGY EET 103/4
Explain and analyze series and parallel circuits
Explain, derive and analyze Ohm’s Law, Kirchhoff Current Law, Kirchhoff Voltage Law, Source Transformation, Thevenin theorem.
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(CHAPTER 8)
METHOD OF ANALYSISMETHOD OF ANALYSIS
SOURCE CONVERSIONSOURCE CONVERSION
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8.2 Current Sources The current source is often described
as the dual of the voltage source. A battery supplies a fixed voltage, and the
source current can vary; but the current source supplies a fixed current to the branch in which it is located, while its terminal voltage may vary as determined by the network to which it is applied.
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8.2 Current Sources
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8.2 Current SourcesA current source determines the current
in the branch in which it is located The magnitude and polarity of the
voltage across a current source are a function of the network to which it is applied
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8.2 Current Sources
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8.2 Current SourcesExample 8.1
Find Vs, V1 and I1:
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8.2 Current SourcesExample 8.1 – solution
mA 101 II
111 RIV
33 10201010
V 200
V 2001 VVs
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8.2 Current SourcesExample 8.2
Find Vs, I1 and I2:
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8.2 Current SourcesExample 8.2 – solution
V 12EVs
V 12EVR
A 34
122
R
VI R
A 43721 III
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8.3 Sources Conversion
An ideal source cannot be converted from one type to the other.
All practical sources – whether they are voltage or current – have some internal resistance.
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8.3 Sources Conversion
Practical voltage source Practical current source
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8.3 Sources Conversion
The equivalence between a current source and a voltage source exists only at their external terminals.
A source and its equivalent will establish current in the same direction though the applied load.
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8.3 Sources Conversion
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8.3 Sources ConversionExample 8.4
(a) Determine IL.(b) Convert the voltage source
to a current source.(c) Using the current source in
(b), calculate the current through RL.
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8.3 Sources ConversionExample 8.4 – solution
LsTL RR
E
R
EI
A 142
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8.3 Sources ConversionExample 8.4 – solution (cont’d)
IA 3
2
6
sR
EI
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8.3 Sources ConversionExample 8.4 – solution (cont’d)
Voltage source Current sourceconverted to
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8.3 Sources ConversionExample 8.4 – solution (cont’d)
Voltage source and its equivalent current source with the same load
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8.3 Sources ConversionExample 8.4 – solution (cont’d)
Lp
pL RR
RII
A 142
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8.3 Sources ConversionExample 8.5
Determine I2:
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8.3 Sources ConversionExample 8.5 - solution
Convert the current source to a voltage source
Note the polarityV 1234111 RIE
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8.3 Sources ConversionExample 8.5 – solution (cont’d)
Reconnect the voltage source E2 and its resistance R2:
V 1751221 EEET
52321 RRRT
A 4.35
172
T
T
R
EI