1 cse524: lecture 11 network layer functions. 2 exam

34
1 CSE524: Lecture 11 Network Layer Functions

Upload: rolf-terry

Post on 28-Dec-2015

221 views

Category:

Documents


1 download

TRANSCRIPT

Page 1: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

1

CSE524: Lecture 11

Network Layer

Functions

Page 2: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

2

Exam

Page 3: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

3

Where we’re at…• Internet architecture and history• Internet protocols in practice• Application layer• Transport layer• Network layer

– Network-layer functions– Specific network layer protocols (IP) and devices

• Data-link layer• Physical layer

Page 4: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

4

Network layer functions• Transport packet from

sending to receiving hosts

• Network layer protocols in every host, router

• Important functions:– Addressing: address

assignment– Delivery semantics: unicast,

multicast, anycast, broadcast, ordering

– Security: provide privacy, authentication, etc. at the network layer

– Fragmentation: break-up packets based on data-link layer properties

– Quality-of-service: provide predictable performance

– Routing: path selection and packet forwarding

networkdata linkphysical

networkdata linkphysical

networkdata linkphysical

networkdata linkphysical

networkdata linkphysical

networkdata linkphysical

networkdata linkphysical

networkdata linkphysical

applicationtransportnetworkdata linkphysical

applicationtransportnetworkdata linkphysical

Page 5: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

5

NL: Demux to upper layer

• Sends payload to the next layer in protocol stack – Usually transport layer– Can be other layers (recall tunneling discussion)

Page 6: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

6

NL: Error detection

• Protection of data and/or header at the network layer– Provide extra protection on top of data-link layer and

below transport layer– End-to-end principle

• Is this necessary?

• IPv6 answer =>No

Page 7: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

7

NL: Delivery semantics

• Communication modes– Unicast (One source to one destination)

– Anycast (One source to any of a set of destinations)

– Multicast (One or more sources to a set of destinations)

– Broadcast (One source to all destinations)

• Ordering– In-order vs. out-of-order delivery

– Recall ATM service models

• If time permits, we will look at multicast at the end of the course.

Page 8: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

8

NL: Security

• Secrecy– No eavesdropping

• Integrity– No man-in-the-middle attacks

• Authenticity– Ensure identity of source

• If time permits, we will look at network security at the end of course…..

Page 9: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

9

NL: Fragmentation

• Different link-layers have different MTUs

– Split packets into multiple fragments– Where to do reassembly?

• End nodes – avoids unnecessary work

• Dangerous to do at intermediate nodes– Buffer space

– Must assume single path through network

– May be re-fragmented later on in the route again

Page 10: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

10

NL: Fragmentation is Harmful

• Uses resources poorly– Forwarding costs per packet– Best if we can send large chunks of data– Worst case: packet just bigger than MTU

• Poor end-to-end performance– Loss of a fragment

• Reassembly is hard– Buffering constraints

Page 11: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

11

NL: Fragmentation

• References– Characteristics of Fragmented IP Traffic on Internet Links.

Colleen Shannon, David Moore, and k claffy -- CAIDA, UC San Diego. ACM SIGCOMM Internet Measurement Workshop 2001. http://www.aciri.org/vern/sigcomm-imeas-2001.program.html

– C. A. Kent and J. C. Mogul, "Fragmentation considered harmful," in Proceedings of the ACM Workshop on Frontiers in Computer Communications Technology, pp. 390--401, Aug. 1988. http://www.research.compaq.com/wrl/techreports/abstracts/87.3.html

Page 12: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

12

NL: Fragmentation

• Remove fragmentation from the network (IPv6)• Path MTU Discovery

– Network layer does no fragmentation– Host does Path MTU discovery– ICMP message for oversized packets

Page 13: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

13

NL: Quality-of-Service

Q: What service model for “channel” transporting packets from sender to receiver?

• guaranteed bandwidth?• preservation of inter-packet

timing (no jitter)?• loss-free delivery?• in-order delivery?• congestion feedback to

sender?

? ??virtual circuit

or datagram?

The most important abstraction provided

by network layer:

serv

ice a

bst

ract

ion

Page 14: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

14

NL: Connection-oriented virtual circuits• Phone circuit abstraction (recall ATM discussion)

– Model

• call setup and signaling for each call before data can flow

• guaranteed performance during call

• call teardown and signaling to remove call

– Network support

• each packet carries circuit identifier (not destination host ID)

• every router on source-dest path maintains “state” for each passing circuit

• link, router resources (bandwidth, buffers) allocated to VC to guarantee circuit-like performance

applicationtransportnetworkdata linkphysical

application

transportnetworkdata linkphysical

1. Initiate call2. incoming call

3. Accept call4. Call connected5. Data flow begins 6. Receive data

Page 15: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

15

NL: Connectionless datagram service• Postal service abstraction (Internet)

– Model

• no call setup or teardown at network layer

• no service guarantees

– Network support

• packets carry only destination host ID

• no state within network on end-to-end connections

• packets between same source-dest pair may take different paths

application

transportnetworkdata linkphysical

application

transportnetworkdata linkphysical

1. Send data 2. Receive data

Page 16: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

16

NL: Best of both worlds?

• Adding circuits to the Internet

– Intserv, Diffserv (at the end of course if time permits)

– Chapter 6 in book

• Start from scratch and redesign

– ATM

Page 17: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

17

NL: Addressing

• Hierarchical vs. flat– Routing table size

• Global vs. local– Applications (NAT)– Processing speed

• Variable-length vs. fixed-length– Flexibility– Processing costs – Header size

Page 18: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

18

NL: Routing

• The most complicated and important function the network layer provides– Directing data from source to destination

• Routing algorithms and architectures– Link state algorithms– Distance vector algorithms

• Routing hierarchies– Area routing– Landmark routing (at end of course time-permitting)

Page 19: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

19

NL: Routing algorithms

Graph abstraction for routing algorithms:

• graph nodes are routers

• graph edges are physical links– link cost

• Delay

• $ cost

• congestion level

Goal: determine “good” path

(sequence of routers) thru network from source to

dest.

Routing protocol

A

ED

CB

F

2

2

13

1

1

2

53

5

• “good” path:– typically means

minimum cost path

– other def’s possible

Page 20: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

20

NL: Routing algorithms

Global or decentralized information?

Global:• all routers have complete

topology, link cost info• “link state” algorithmsDecentralized: • router knows physically-

connected neighbors, link costs to neighbors

• iterative process of computation, exchange of info with neighbors

• “distance vector” algorithms

Static or dynamic?Static:

• routes change slowly over time

Dynamic:

• routes change more quickly

– periodic update

– in response to link cost changes

Page 21: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

21

NL: What to look for in routing algorithms

• Communication costs

• Processing costs

• Optimality

• Stability– Convergence time– Loop freedom– Oscillation damping

Page 22: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

22

NL: Link state routing algorithms

• Used in OSPF (intra-domain routing protocol)• Basic steps• Start condition

– Each node assumed to know state of links to its neighbors

• Step 1– Each node broadcasts its local link states to all other nodes– Reliable flooding mechanism

• Step 2– Each node locally computes shortest paths to all other nodes

from global state– Dijkstra’s shortest path tree (SPT) algorithm

Page 23: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

23

NL: Step 1

• Link State Packets (LSPs) to broadcast state to all nodes

• Periodically, each node creates a link state packet containing:– Node ID– List of neighbors and link cost– Sequence number– Time to live (TTL)– Node outputs LSP on all its links

Page 24: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

24

NL: Step 1

• Reliable Flooding – When node J receives LSP from node K

• If LSP is the most recent LSP from K that J has seen so far, J saves it in database and forwards a copy on all links except link LSP was received on

• Otherwise, discard LSP

– How to tell more recent• Use sequence numbers

– Same method as sliding window protocols

– Needed to avoid stale information from flood

– Problem: sequence number wrap-around

» Lollipop sequence space

Page 25: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

25

NL: Step 1 and wrapped sequence numbers

• Wrapped sequence numbers– 0-N where N is large– If difference between numbers is large, assume a

wrap– A is older than B if….

• A < B and |A-B| < N/2 or…• A > B and |A-B| > N/2

• What about new nodes or rebooted nodes that are out of sync with sequence number space?– Lollipop sequence (Perlman 1983)

Page 26: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

26

NL: Step 1 and lollipop sequence numbers

• Divide sequence number space• Special negative sequence for recovering from reboot

– New and rebooted nodes use negative sequence numbers

– Upon receipt of negative number, other nodes inform these nodes of current “up-to-date” sequence number

• A older than B if – A < 0 and A < B– A > 0, A < B and (B – A) < N/4– A > 0, A > B and (A – B) > N/4

0-N/2

N/2 - 1

Page 27: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

27

NL: Step 2

Dijkstra’s algorithm• all link costs on the network

are known• all nodes have same info• computes least cost paths

from one node (‘source”) to all other nodes– gives routing table for that

node• iterative: after k iterations,

know least cost path to k destinations

Notation:• c(i,j): link cost from node i

to j. cost infinite if not direct neighbors

• D(v): current value of cost of path from source to dest. V

• p(v): predecessor node along path from source to v, that is next v

• N: set of nodes whose least cost path definitively known

A Link-state routing algorithm

Page 28: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

28

NL: Step 2 (Dijkstra’s algorithm example)

1 Initialization: 2 N = {A} 3 for all nodes v 4 if v adjacent to A 5 then D(v) = c(A,v) 6 else D(v) = infinity 7 8 Loop 9 find w not in N such that D(w) is a minimum 10 add w to N 11 update D(v) for all v adjacent to w and not in N: 12 D(v) = min( D(v), D(w) + c(w,v) ) 13 /* new cost to v is either old cost to v or known 14 shortest path cost to w plus cost from w to v */ 15 until all nodes in N

Page 29: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

29

NL: Step 2 (Dijkstra’s algorithm example)

A F

B

D E

C2

2

2

3

1

1

1

3

5

step SPT D(b), P(b) D(c), P(c) D(d), P(d) D(e), P(e) D(f), P(f)

0 A 2, A 5, A 1, A ~ ~

5

B C D E F

Page 30: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

30

NL: Step 2 (Dijkstra’s algorithm example)

A F

B

D E

C2

2

2

3

1

1

1

3

5

step SPT D(b), P(b) D(c), P(c) D(d), P(d) D(e), P(e) D(f), P(f)0 A 2, A 5, A 1, A ~ ~1 AD 2, A 4, D 2, D ~

5

B C D E F

Page 31: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

31

NL: Step 2 (Dijkstra’s algorithm example)

A F

B

D E

C2

2

2

3

1

1

1

3

5

step SPT D(b), P(b) D(c), P(c) D(d), P(d) D(e), P(e) D(f), P(f)0 A 2, A 5, A 1, A ~ ~1 AD 2, A 4, D 2, D ~2 ADE 2, A 3, E 4, E

5

B C D E F

Page 32: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

32

NL: Step 2 (Dijkstra’s algorithm example)

A F

B

D E

C2

2

2

3

1

1

1

3

5

step SPT D(b), P(b) D(c), P(c) D(d), P(d) D(e), P(e) D(f), P(f)0 A 2, A 5, A 1, A ~ ~1 AD 2, A 4, D 2, D ~2 ADE 2, A 3, E 4, E3 ADEB 3, E 4, E

5

B C D E F

Page 33: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

33

NL: Step 2 (Dijkstra’s algorithm example)

A F

B

D E

C2

2

2

3

1

1

1

3

5

step SPT D(b), P(b) D(c), P(c) D(d), P(d) D(e), P(e) D(f), P(f)0 A 2, A 5, A 1, A ~ ~1 AD 2, A 4, D 2, D ~2 ADE 2, A 3, E 4, E3 ADEB 3, E 4, E4 ADEBC 4, E

5

B C D E F

Page 34: 1 CSE524: Lecture 11 Network Layer Functions. 2 Exam

34

NL: Step 2 (Dijkstra’s algorithm example)

A F

B

D E

C2

2

2

3

1

1

1

3

5

step SPT D(b), P(b) D(c), P(c) D(d), P(d) D(e), P(e) D(f), P(f)0 A 2, A 5, A 1, A ~ ~1 AD 2, A 4, D 2, D ~2 ADE 2, A 3, E 4, E3 ADEB 3, E 4, E4 ADEBC 4, E5 ADEBCF

5

B C D E F