sijil pelajaran malaysia 2010 matematik tambahan kertas 1 skema jawapan peperiksaan percubaan sijil...

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  • http://chngtuition.blogspot.com

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  • SULIT

    3472/1 © 2010 Hak Cipta Jabatan Pelajaran Selangor SULIT

    PROGRAM PENINGKATAN PRESTASI AKADEMIK 3472/1 SIJIL PELAJARAN MALAYSIA 2010 Matematik Tambahan Kertas 1

    SKEMA JAWAPAN PEPERIKSAAN PERCUBAAN

    SIJIL PELAJARAN MALAYSIA 2010

    MATEMATIK TAMBAHAN

    Kertas 1

    PERATURAN PEMARKAHAN

    UNTUK KEGUNAAN PEMERIKSA SAHAJA

    Peraturan Pemarkahan ini mengandungi 4 halaman bercetak

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  • SULIT 2 3472/1

    3472/1 © 2010 Hak Cipta Jabatan Pelajaran Selangor SULIT

    1 (a)

    2 3

    t

    (b) 0 ≤ f(x)≤13

    1

    2

    6

    p = – 2 and q = – 5

    p = – 2 or q = – 5

    (x + 2)2 – 5

    3

    B2 B1

    3

    2

    2

    (a)

    2 11)4( f

    2 324  x

    (b) 1k

    2 1

    2 3)2(2 

    k

    B1

    2

    B1

    7

    2x

    9 13 x

    23 3333  xx

    or equivalent

    B2

    B1

    3

    (a) 16x –5

    4(4x – 1) – 1 (b) a =8 and b = 5 a =8 or b = 5

    1

    2 B1

    4

    2x2–11x– 6=0 (x– 6)(x +

    2 1 ) = 0 or equivalent

    2

    B1

    8 9

    x = 243

    5log 3 x

    5log 22 3 x

    2 3

    y = 9 or G.P : 8, 12, 18 y2 – 8y – 9 = 0 or

    3 2

    1 3

     

     

    y y

    y y

    3

    B2

    B1

    3

    B2

    B1

    5

    2 < k < 6 (k – 2)(k – 6) < 0 k2–4(1)(2k – 3)< 0

    3

    B2

    B1

    10

    n = 5

    729)3(9 1 n

    2

    B1

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  • SULIT 3 3472/1

    3472/1 © 2010 Hak Cipta Jabatan Pelajaran Selangor SULIT

    11

    –1

    [ 8] – [9] S4 = [24-16] or equivalent OR S3 = [18 – 9] or equivalent

    3

    B2

    B1

    15

    (a) 1 : 2

    37   

    nm nm

    (b) 4

    2

    B1

    1

    12

    (a) 1

    1cos 2 

     p

    (b) 21 2

    p p

      

       

      

       

     1 1

    1 2

    22 pp p or

    equivalent

    1 2 B1

    16

    8

    bamba 9)2()64(  ,

    2

    9 4 6

     

    m

    or equivalent

    2

    B1

    13

    h = 3 1 and k = –2

    h = 3 1 or k = –2

    231  kor h

    gradient = 2 or

    h

    kx y

    11 

    4

    B3

    B2

    B1

    17

    (a) ba 68  (b) ba 34 

     abbKH 86 2 16 

    or equivalent

    1

    2

    B1

    14

    (a) 3 (b) 05422  yyx 3)( 22  yx

    1

    2

    B1

    18

    (a) 2. 5 radian

    45.92)6.8( 2 1 2 

    (b) 21.5cm 5.26.8 

    2 B1 2 B1

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  • SULIT 4 3472/1

    3472/1 © 2010 Hak Cipta Jabatan Pelajaran Selangor SULIT

    19

    8 3

    a and b = 3

    8a + 2b = 3 or 8a + b = 0 4ax + b = 0

    3 B2 B1

    23

    (a) 84 (b) 30 2

    4 4

    5 CC  2

    4 4

    5 CorC

    1 3 B2 B1

    20 (a) 2

    3 p

    2

    12 

     p

    (b) 4

    2)( 1

    xpdx dy

     

    2 B1 2 B1

    24

    (a) 18 5

    (b) 18 11

    6 5

    3 2  +

    6 1

    3 1 

    6 5

    3 2  or

    6 1

    3 1 

    1 3 B2 B1

    21

    (a) – 4 (b) k = 2 0)2)(4(  kk or

    kk  

    

      

    2 )2(

    2 4

    2 1 22

    k xor

    2

    2

    2 4

    2 1

     

     

     

    1 3 B2 B1

    25

    (a) k = 1.03 8485.01)(  kzP (b) 198

    1515.0 30

     n

    2 B1 2 B1

    22

    (a) m = 14 (b) std deviation = 4.598

    212 7

    1156 

    1

    2

    B1

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